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Put a closed cylindrical surface in an electric field. If the field is uniform and no charge lies inside the cylinder, the net electric flux through the cylinder is zero. If a net charge Q is inside, the net flux is Q/ε0. That is the direct answer to the textbook question, and it follows from Gauss's law. The real work is deciding which charge the cylinder actually encloses.
The word "net" matters. Field lines can enter one cap and leave the other, or enter the curved side and leave elsewhere. The net electric flux is the algebraic sum of all contributions over the whole closed surface. For a closed cylinder, Gauss's law turns that sum into a simple charge count.
Electric flux measures how much electric field passes through a surface. For a small patch of area dA, the flux is E cosθ dA, where θ is the angle between the electric field vector and the outward normal to the surface. Integrating over the entire closed cylinder gives the net electric flux. If more field lines leave than enter, the flux is positive. If more enter than leave, it is negative.
In introductory physics, flux is usually expressed in N·m²/C. You can think of it as the net amount of electric field crossing the surface, although it is not a physical substance. It is a calculated quantity that makes Gauss's law useful.
Gauss's law states that the outward electric flux through any closed surface equals the enclosed net charge divided by the vacuum permittivity:
Φ = Qenc/ε0
Here, Qenc is the total charge inside the closed surface, and ε0 is the vacuum permittivity, approximately 8.85 × 10-12 C²/(N·m²).
Three conclusions follow directly from the equation:
Textbook problems use a cylinder because it is a closed surface with a simple shape. A closed cylinder has three parts: the left flat cap, the right flat cap, and the curved lateral surface. Each part has a known normal direction, so the flux through each part can be evaluated separately.
| Surface part | Relation to the field | Flux contribution |
|---|---|---|
| Left flat cap | Outward normal points against the field | −EA |
| Right flat cap | Outward normal points with the field | +EA |
| Curved lateral surface | Surface normal is perpendicular to the field | 0 |
| Whole closed cylinder | No enclosed charge | 0 |
If the uniform field is perpendicular to the cylinder axis, the end caps contribute zero and the curved side also integrates to zero. The conclusion is the same: a uniform field produces no net flux through a closed cylinder unless a charge is inside it.
Use this sequence on homework and exam problems:
For a uniform electric field and a closed surface with no enclosed charge, the net flux is always zero. You do not need to integrate the curved side. The entering field lines balance the leaving field lines.
Most questions about net electric flux through a cylinder fall into a small number of cases. Once you identify the enclosed charge, the answer is straightforward.
| Case | Enclosed charge | Net electric flux |
|---|---|---|
| Cylinder in a uniform electric field with no charge inside | 0 | 0 |
| Point charge q at the center of the cylinder | q | q/ε0 |
| Cylinder around a long line of charge with linear density λ and length L | λL | λL/ε0 |
| Cylinder with equal positive and negative charges inside | 0 | 0 |
Notice that the radius and the exact position of the charge inside the cylinder do not appear in the final flux value. Once the enclosed charge is known, the cylinder shape only matters if you also need to find the electric field at the surface.
If an answer seems too complicated, return to Qenc. The algebra may be long, but the physics of net flux is a charge-counting problem.
The cylinder in a flux problem is an imaginary surface, not a mechanical part. In industrial automation, a cylinder can also be a physical actuator that converts rotary motor torque into linear motion. Although Gauss's law does not affect that choice, the term "cylinder" appears in both contexts, so it is useful to separate the physics meaning from the equipment meaning.
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The net electric flux through a closed cylinder is Qenc/ε0. For an uncharged cylinder, or for a cylinder placed in a uniform electric field with no charge inside, that flux is zero. For a cylinder that surrounds a net charge, the flux equals the enclosed charge divided by the vacuum permittivity. Keep the surface closed, count only the charge inside, and apply Gauss's law. The cylinder's dimensions will not change the net flux.
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